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Join date: May 16, 2022

Category:Surgical booksQ: Generate map of pairs from pair of lists I need to generate a map of pairs of two lists of the same length and return a flat list of all pairs, as in: (a b) (a b c) (a b c d)... I want the order of the values not to matter, and for the output to be easy to process from left to right: I do not want the result to be in the order (a b) (a c), but rather (a b) (a c) (a d), or even more, (a b) (a c) (a d) (a e). What is the cleanest way to generate the map? A: Pairs(from a to b)(from a to c)(from a to d)... can be written as (->a)(->b)(->c)(->d)... or similar. This works by generating a list of "pairs" of all permutations of (->a)(->b)... and then forming a tuple of the top-level results (for the same number of a,b,c, etc.). The generator below works by forming a function that will take a list of (->a)(->b)... and return the next pair from the list in some order. This is pretty common - defining a function to take in all elements of a list and generate the list of (->a)(->b)... for each item in that list. (defn pairs "Generates the list of pairs from two lists. The first list is considered to be the first in the pair and the second is considered to be the second in the pair. For example, '(a b) (a c) (a d) (b c) (b d) should be returned." [x y] (->x y)) (defn generate "Generate a function that can be applied to a list to produce the next pair." [f] (let [gen ; function to generate pair g

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